PROSAGA码农传奇-JS-检查民事号码的算法

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   <pre>
    <code>
      var checkCivilNumber = function(number) {
  var coef  = [2, 4, 8, 5, 10, 9, 7, 3, 6],
      sum = 0;
  for (var i = 0; i < number.length - 1; i++) {
    sum += parseInt(number[i]) * coef[i];
  }
  return (((sum % 11) % 10) == number[number.length-1]);
}

</code>
  </pre>
  <UL>
    <LI>
      系数是相反的
    </LI>
    <LI>
      在计算和模11之后，计算结果模10，使得10根据算法变为0
    </LI>
  </UL>
  <P>
    测试：
  </p>
   <pre>
    <code>
      console.log(checkCivilNumber("7523169263"));
console.log(checkCivilNumber("8032056031"));
console.log(checkCivilNumber("8001010008"));
console.log(checkCivilNumber("7501020018"));
console.log(checkCivilNumber("7552010005"));
console.log(checkCivilNumber("7542011030"));

</code>
  </pre>
  <P>
    这是获取细节的功能。可以使用子字符串提取字段，然后根据规则进行调整。我会让你正确地格式化输出：
  </p>
   <pre>
    <code>
      var civilNumberDetails = function(number) {
   var year = parseInt(number.substring(0,2)) + 1900;
   var month = parseInt(number.substring(2,4));
   var day = parseInt(number.substring(4,6));
   if(month > 40) // years from 2000-2099 have 40 added to the month
   {
       month -= 40;
       year += 100;
   }
   if(month > 20) // years from 1800-1899 have 20 added to the month
   {
       month -= 20;
       year -= 100;
   }
   // check odd/even of 9th digit using bitwise operator:
   var gender = (parseInt(number[8]) & 1) ? "F" : "M";
   console.log(year + "-" + month + "-" + day + " " + gender);
}

</code>
  </pre>
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